Ҳосилаи тартиби дуюми функсияи зерин ёфта шавад:
\[y = (3x+5)^6.\]

Ҳал.
\(y' = \left( (3x+5)^6 \right)' = 6\cdot (3x+5)^{6-1}\cdot (3x+5)'=6\cdot (3x+5)^{5}\cdot 3=18(3x+5)^{5}.\)

\(\begin{multline}
y'' = \left( 18(3x+5)^{5} \right)'=18((3x+5)^{5})'=18\cdot 5\cdot (3x+5)^{5-1}\cdot (3x+5)'=\\
=90\cdot (3x+5)^4\cdot 3=270(3x+5)^4.
\end{multline}\)

Ҷавоб.

\[y'' = 270(3x+5)^4.\]